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cherylmj01 Posts: 13	Posted 16:12 Jun 06, 2016 \| pin(b2), pin(b1), pin(b1), unpin(b2), unpin(b1), unpin(b2) The PIN COUNT for b2 is 2 unpin(b2) appears 2 times here, so does that mean that the first time we unpin the pin count becomes 1 and the next time we unpin then the pin count becomes 0 ?
ngosrani Posts: 31	Posted 16:15 Jun 06, 2016 \| yes, that is correct. but I see only one pin(b2) in the sequence Last edited by ngosrani at 16:18 Jun 06, 2016.
cherylmj01 Posts: 13	Posted 16:42 Jun 06, 2016 \| cherylmj01 wrote: pin(b2), pin(b1), pin(b1), unpin(b2), unpin(b1), unpin(b2) The PIN COUNT for b2 is 2 unpin(b2) appears 2 times here, so does that mean that the first time we unpin the pin count becomes 1 and the next time we unpin then the pin count becomes 0 ? Sorry that was my mistake. It should be pin(b2), pin(b1), pin(b2)... unpin(b2), unpin(b1), unpin(b2)