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bpatel1
Posts: 8
Posted 17:59 Dec 08, 2014 |

How to solve this??

Consider a video format with 325 lines/frame, 490 pixels/line, 30 frames/s, color subsampling scheme 4:2:2, image aspect ratio:
4:3. Compute the bit-rate of the system (assuming each luminance and chrominance sample is quantized with 8 bits).

 

Sparikh2
Posts: 5
Posted 18:21 Dec 08, 2014 |

325*490*16*30=76440000 bits =76.44 MBits where 16 is the avg pixel per bit...

Last edited by Sparikh2 at 18:24 Dec 08, 2014.
rpuas
Posts: 29
Posted 23:21 Dec 08, 2014 |

The calculation depends on the subsampling scheme. The 4:2:2 means the Cb & Cr are 1/2 of the Y horizontal resolution.

Y bits = 325 * 490 * 30 * 8 = 38,220,000 bits

Cb bits = 325 * (490 / 2) * 30 * 8 = 19,110,000 bits

Cr bits = 325 * (490 / 2) * 30 * 8 = 19,110,000 bits

Total = 76,440,000 bits = 76.44 Mbits