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Vanquish39
Posts: 134
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Posted 02:47 Oct 16, 2012 |
Can someone please show me online, book, or video on how I can add a tuple to a list.... I've been stuck on this for an hour.
var yy = List[(Char, Int)](('a', 2), ('b', 3), ('c', 1));
var pair: (Char, Int) = ('c', 111) how can i add pair to yy? I've tried yy :+ pair and other functions none of which work. Any idea? |
frodrig3
Posts: 2
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Posted 03:22 Oct 16, 2012 |
I found something that works, but it doesn't look intuitive to me. I'm certain there's a better way to do it, but in the mean time:
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Vanquish39
Posts: 134
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Posted 03:28 Oct 16, 2012 |
so how does one alter the count value in the tuple? Lol Delete and re-add? Last edited by Vanquish39 at
03:29 Oct 16, 2012.
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asmiths
Posts: 12
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Posted 11:42 Oct 16, 2012 |
I have been using the operator "::" to concatenate lists and the objects that belong in them, for instance: objectA :: List[Object] will return a List[Object] with the objectA at the head of the original List[Object]
Correction: list1 :: list2 doesn't work.
So, in order to replace the Int in the List[(Char, Int)], we cannot just say Int = Int + 1. What we do instead, is replace the list item with a new one of (Char, Int + 1). If you wanted to change the object at the head of someList[(Char, Int)], you would want to then concatenate: (Char, Int + 1) :: someList.tail Last edited by asmiths at
17:43 Oct 16, 2012.
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rabbott
Posts: 1649
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Posted 20:18 Oct 16, 2012 |
What ASMITHS said is correct. The :: operator adds an element to the front of a list. So to use the original example, val newList1 List([Char, Int)] = pair :: yy creates list called newList1, whose head is pair and whose tail is yy, i.e., the list List( (c,111), (a,2), (b,3), (c,1)) The operator :+ adds an element to the end of a list.
val newList2 = yy :+ pair
creates: List((a,2), (b,3), (c,1), (c,111))
Finally, the operator ::: concatenates two lists.
val newList3 = newList1 ::: newList2
creates List( (c,111), (a,2), (b,3), (c,1), (a,2), (b,3), (c,1), (c,111))
Last edited by rabbott at
20:19 Oct 16, 2012.
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