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jpascua
Posts: 197
Posted 12:59 Oct 14, 2012 |

 

2.5. Write a program to read the value of n and calculate the following series.

1 + 1/3 + 1/5 + 1/7 + ... + 1/(2n-1)

For this question of the lab, I don't fully understand what are we supposed to do.

rframe
Posts: 18
Posted 15:06 Oct 14, 2012 |

What exactly is it that you do not understand?

if its the equation it is

1 / (2(1) - 1) + 1 / (2(2) - 1) + 1 / (2(3) - 1) + 1 / (2(4) - 1) + ... + 1 / (2(n) - 1) 

Last edited by rframe at 15:06 Oct 14, 2012.
jpascua
Posts: 197
Posted 15:08 Oct 14, 2012 |

Well, is the value of "n" supposed to be given or does the user input the value?

rframe
Posts: 18
Posted 15:25 Oct 14, 2012 |

That part is probably left to your choice, what chapter of the book are you guys on?

jpascua
Posts: 197
Posted 15:27 Oct 14, 2012 |

Chapter 4 (Loops).

rframe
Posts: 18
Posted 15:39 Oct 14, 2012 |

1/2n-1 is going to approach 0 

so what I would do if I was writing the program is use a large  value for n

jpascua
Posts: 197
Posted 15:41 Oct 14, 2012 |

So the user has to input a large value for "n"?

rframe
Posts: 18
Posted 15:43 Oct 14, 2012 |

I would sent the n to a large value

rframe
Posts: 18
Posted 15:43 Oct 14, 2012 |

But like I said that seems like your choice

rframe
Posts: 18
Posted 15:44 Oct 14, 2012 |

becareful because if your output is 1 then you have an error

hpguo
Posts: 139
Posted 22:42 Oct 14, 2012 |

Just make it clear that the user can type any positive integer for  n.  Here are some examples of n and the corresponding value of the series.:

n                    value

1                     1

2                     1+1/3

3                     1+1/3+1/5

4                     1+1/3+1/5+1/7

100                 1+1/3+1/5+1/7+...+1/199