1) Question 2 - d, 

A) In standard SI usage, 1 terabyte (TB) equals 1000000000000bytes = 10004, or 1012 bytes.

B) Using the traditional binary interpretation, a terabyte would be 1099511627776bytes = 10244 = 240 bytes = 1 tebibyte (TiB).

Can you tell which value we should consider for 1 TB? option A or B.

 

2) As per my understanding, "All base cells are closed cells".

In question 3, It is given that,  The base cuboid of 10 dimensional cube contains only three non-zero cells:

(a1,a2,a3,b4,b5,b6,b7,b8,b9,b10)

(b1,b2,b3,b4,b5,b6,b7,b8,b9,b10)

(a1,a2,a3,b4,b5,b6,b7,c8,c9,c10).

 

As per the above 3 cells data, 

Dimension 1, 2 and 3 have distinct value {ai, bi} where i = 1,2,3 and

Dimension 8, 9 and 10 have distinct value {bj, cj} where j = 8,9,10

 

or can we say,

Dimension 1,2,3,8,9,10 have cardinality [distinct tuple] = 2 and

Dimension 4,5,6,7 have cardinality [distinct tuple] = 1

 

Should we consider all the possible combination of all zero base cells to calculate the closed cells? since all the base cells are closed cells

I am assuming that only above 3 cells have measure "count" non zero, and rest of the possible base cell have measure count "zero".